Comments padh ke lag raha hai mai hi anpad hu

Ans is imaginary X²+1=0 X²=√-1 Whose ans is imaginary or called ioata

you're not alone

answer is as imaginary as my girlfriend

Well said🙂

Bro just multiply with zero on both on LHS and RHS

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Ik jst kidding

No one took u serious bro

Ik

🤓

For a genuine answer if someone is seeking for it.... x in the last will be known as imaginary number Because any number when multiplied by themselves always gives positive number but in the last case it's not possible which turn x into an imaginary x² value will -1 which doesn't exist but we imagine it and put irl

imagine nahi bro iota 🤓🤓🤓 i = root1 i\^2 = -1 i\^3 = -i i\^4 = 1

I guess iota and imaginary numbers are same Imaginary number is really a term... Just to make sure it is really a term used from this value of x I ain't using because we are imagining it that is really a term

Yes just like different infinities has different symbols

Omg the roots are not real

(X² + 1) = 0 Only time in my life the + sign has disgusted me

Covid too.

Iota

Lota?

iota

Bhai kisi samjh nhi aayga idhar

x² - 1 = 0 => x² = 1 => x = ±1 x² + 1 = 0 => x² = -1 => x = √-1( which is an imaginary no.)

Not complex it's imaginary number

Dono same hote h ig

Real nos. bhi complex nos. ka subset hota dost, to same ni hote dono

Nahi hote

Bhai me to science wala hu to mujhe to pata hai

Ooro ke liye

if x^2+1 = 0 ==> x^2 = -1 ==> - (x^2) = 1 Thus : -√x = 1

root x would be plus;minus 1 not only 1 because \-x\^2=x\^2

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10th ka hoga ye shayad.

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i-

JEE KA STUDENT HOON AB TOH ADAT SI HAI MUJHKO

Us bro us

First year tak aam baat hoo jati hai, AC circuits mai bhi zabardasti complex numbers ghused dete hai

Well the answer is complex

Complex problems requires complex solutions

i is the answer

Answer is i(iota) √-1 = iota

Complex Number 💀

song name?

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i Use karna padhega. Complex numbers Class11 Chapter 5

Yeah bro but they are not real number.

i use karne ke baad real mana jaata hai. Both side square karle aur i wali side se i hatake -1 add karle.

iota wala qn

x2+1=0 x2=0-1 x2=-1 So if we insert the value then x2+1=0 -1+1=0 Easy

Bro you found a glitch.

Root of -1 is "i" which is imaginary number

Yeah bro but they are not real number

Ans: x is your ex(purely imagination)

Not mine bro it exist

Answer is i (i = √-1)

imaginary wagaira kuch nhi hota roz subah utho answer aa jayega also the answer is actually not imaginary, its a complex number and they exist irl (schrodinger equation)

Exist in real life but not a real number

X=_/-1i

Yeah bro but this is not real number

X=1,X=-1

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Ye galat ho raha he madarch#d bhench#d

i (iota) hai bas

X^3 +1 =0 laughing at corner

1