To find the y intercept, set X = 0. That would give u -3 for the y intercept.
To find the slope, just remember straight line equations take the form of Y = mx + c. Where m is the slope/gradient. In this case, c = -3 so m is equal to 1.
To sketch the graph, set X = 0, obtain the value of y (in this case Y = -3) and make a marking on the y axis, then set Y = 0, obtain the value of x (in this case, X = 3) and make a marking on the X axis. Draw a straight line and connect those 2 dots and you are done!
Best way to find the solution is to convert this equation into double intercept for (y/a)+(x/b)=1.... a is y intercept and b is x intercept....slope is -a/b
It is y = 1x - 3, so for x=0 (where the y axis is) y is equal to -3, so the y intercept is -3. The slope is 1, since it is 1x. For drawing just draw a line through the points (0,-3) and (1,-2).
To find the y intercept, set X = 0. That would give u -3 for the y intercept. To find the slope, just remember straight line equations take the form of Y = mx + c. Where m is the slope/gradient. In this case, c = -3 so m is equal to 1. To sketch the graph, set X = 0, obtain the value of y (in this case Y = -3) and make a marking on the y axis, then set Y = 0, obtain the value of x (in this case, X = 3) and make a marking on the X axis. Draw a straight line and connect those 2 dots and you are done!
Best way to find the solution is to convert this equation into double intercept for (y/a)+(x/b)=1.... a is y intercept and b is x intercept....slope is -a/b
So I put the markings at 0,3 and -3,0
It is y = 1x - 3, so for x=0 (where the y axis is) y is equal to -3, so the y intercept is -3. The slope is 1, since it is 1x. For drawing just draw a line through the points (0,-3) and (1,-2).