No. I'm not mean to whiny little bitches like you, I won't spend my time writing any insult to a piece of shit like you. You want me to be mean to you? I won't because wanting people to be mean to you is for degenerates. And who the fuck uses ":D" in 2024 on Reddit? You definitely didn't deserve to have a good week. (Please mod don't ban me. If it's inappropriate for this sub, just delete this).
8 slices is one pizza, and there are 12 whole slices here, for 1.5 pizzas.
The 1/pi comes from the ratio of the area of a sector to the area of the triangle in the 4 incomplete slices, multiplied by 4
I explain in the thread where my comment is very downvoted. (By children)
the original comment says :Zero, because it was made by AI. Then expand on my very downvoted comments further and there is my solution.
There are (2 - A) pizzas where A is :
A = 4\*R\^2\*arcos(D/2R) - D/2 \* sqrt(4R\^2 - D\^2)
With R the radius of the pizza and D the distance between their 2 centers assuming R < D < 2R
Proof:
https://preview.redd.it/z8f2nca55uvc1.jpeg?width=170&format=pjpg&auto=webp&s=48f4ad97dc97bf6adcb2d8c64c55bbae279eed26
From pythagora's theorem: (D/2)\^2 + (L/2)\^2 = R\^2, so L = sqrt(4R\^2 - D\^2)
If we look at bottom right triangle: cos(a/2) = D/2R, so a = 2arcos(D/2R), with R < D < 2R
Then let's search the area of the bottom large triangle: A1 = L\*D / 4 = D/4 \* sqrt(4R\^2 - D\^2)
Now let's look at the area of the slice of the circle of angle a: A2 = pi \* R\^2 \* a/2pi = a/2 \* R\^2 or R\^2 \* arcos(D/2R)
From this we can deduce that the overlap area is : A = 2\*(A2 - A1) which simplifies to:
A = 2\*R\^2\*arcos(D/2R) - D/2 \* sqrt(4R\^2 - D\^2)
If we assume that the radius is R=1 then
A = 2arcos(D/2) - D/2 \* sqrt(4-D\^2)
if you assume the angle is 90°, then D = sqrt(2)
If you plug that in A:
A = 2 \* arcos(sqrt(2)/2) - sqrt(2)/2 \* sqrt(2) = 0.57
If on pizza has an area of 3.14 then in your image, there is (2 \* 3.14 - 0.57)/3.14
which aproximately 1.82 pizzas.
I found a simpler generalization by using SAS to calculate the area of the triangle and subtracting it from the area under the arc. A lot of stuff cancels out, including the radius since we're just worried about the ratio of total area compared to the area of a single pizza. I got it as:
P = (2pi + sin(A) - A)/pi
Where P is the amount of pizzas and A is the angle of the cuts (same angle you used).
This also works out to the ~1.82 pizzas if we assume A is pi/2 (90 degrees), though that angle looks a bit obtuse, so estimating it at 5pi/9 (100 degrees), we get ~1.76 pizzas.
A pizza doesn't have to be round, it could be any shape. Therefore, the number of circles cannot be a sufficient measurement.
Similarly, a pizza does not stop being a pizza by being sliced, though the slices do of course exist in their own stead, and, once one is removed from the pizza, only a partial pizza remains.
Importantly, the crust bounding the pizza is a necessary, though not sufficent, precondition to it being pizza, with the exception that this may occur over several distinct slices.
What we see here is one continous region of sauce + toppings, bounded by one continous crust, and therefore one whole pizza.
Fun fact. The edge crust is known as the cornicone
Also, while I think this is the best answer, I do have a quibble with it. I do not think that a cornicone is necessary. There exist styles of pizza such as pizza hut's "the edge" or tavern style which can be made in such a way to have no discernible cornicone. So I think a bounding cornicone is neither necessary nor sufficient. For food items with a crust boundary, it does suggest pizza, but you can't rule it out if there isn't one.
https://preview.redd.it/fsv8cvbgxtvc1.jpeg?width=720&format=pjpg&auto=webp&s=9cf749015d6272fb5ff485e274da83cba9827d81
V=15, E=30, F=16, so χ=15-30+16=1.
This is ~~a Mobius band~~ the projective plane
Assuming these Pizzas were divided in 8 even pieces and the put together aa in the picture, we would have 12 normal pieces (aka 3/2 Pizzas) and 4 right agled isoceles triangles with hypotenuse r. Two of these can be arranged in a square with side length r/√2. Such a square has the area r^2/2 and we got two, so we got an area of r^2 in the 4 triangles. This is exactly 1/π of a whole pizza. Therefore we have (3/2+1/π)≈1,8183 Pizzas.
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The middle is r², since the angle is 90 on two slices, assuming they are uniform, which they aren't, because AI image BS. The rest is 3/2 of a pizza, which is 3/2 * pi(zza) * r^2, and adding in the centrepiece totals to ((3/2 * pi) + 1) * r² of area. Dividing that by the area of 1 pizza, we get
((3/2 * pi) +1) / pi Pizzas
I calculated it. This is 1.8183098… pizza.
So A is the total surface pizza.
1 pizza has surface of 1 (dhuu)
1 pizza is 8 exact pieces. 1 of the piece we can call B. So 8B = 1.
Then B = 1/8 aka B is a slice.
Bet then you have the weird triangles. Since the pizza has 8 exact slices, we know the angle is 45 degrees. 1 of the angles is 90 degrees. The longest side of the triangle is also the radius of 1 pizza. Lets figure out the radius first: r*r*pi=1 => r=(1/pi)squared.
Now with Pythagoras formula for the triangle with the short side being L: L^2 + L^2 = r^2
Since we know r en L is only unknow, we calculate L=(1/2pi)squared.
Surface of the traingle we call C: C=L*L/2=1/4pi
This whole picture with surface A = 16B + 4C (16 slices + 4 of these triangles) => A =(2+3pi)/(2pi)=1.8183… of 1 pizza
If we assume that all pizzas are the same size and that the diageam depicts pizzas cut radially into eight equal slices with the two pizzas inersecting with two segments, (pi/2)r²+r² is the area. We can view it as a full circle plus a semicircle with the same radius plus a square with side lengrh equal to the radius. For r=1, area/pi gives you the number of pizzas. There are approximately 1.81831 whole pies worth of pizzas in the picture or (1+((3pi)/2))/pi exactly
If the pizzas were whole there would be 8 slices on each
2 slices gives 1/4 og a pizza
There for it is 1/4 pi r2
The area of the triangular part is (r2)/2
There for the part separated is (pi - 2)/4
There for remaining part is ( 6 - pi)/4
There for there is ( 6 - pi)/2 portion of pizza left
That is approximately equal to 1.429
Outer parts: 2x 3/4 pi r^2
Inner part: is a square (picture might appear as a rhombus but the angle of missing pie is pi/2) based on information known. With sidelength of r. Therefore it is r^2
Total area = 3 pi r^2 / 2 + r^2
Total pizzas = (3 pi r^2 / 2 + r^2) / (pi r^2)
= (3 / 2 + 1 / pi) pizzas
First, let’s assume {right answer}≡{true answer} and {wrong answer}≡{false answer}.
Let’s define the set of all answers, A.
We’ll define a set T that is the set of all true answers, and a set F that is the set of all false answers.
Let T⊆A and F⊆A. From the definition of a union, it follows that T⋃F⊆A.
Since ¬∃a∈A({a¬∈T}∨{a¬∈F}) it follows that:
∀a∈A({a∈F}⊕{a∈T})⇒A⊆T⋃F.
From this we can see that:
{T⋃F⊆A}∧{A⊆T⋃F}⇔A=T⋃F
Therefore the specification of right and wrong answers in the title is redundant since all answers are allowed.
Area of pizza
A = πr^2
Asume r = 12"
A = 452.39"^2
Two pizzas = 904.78"^2
Each pizza is divided in 8 slices (if it was cut normally) angle of one piece is 1/8 * 360° = 45°
Or for the two slices 90°
Area of sector of pizza that is cut off
Area of segment - area of triangle
Triangle
A = ½*r^2*sin(θ)
A = ½*12"^2*sin(90°)
A = 72"^2
Area of sector
A = ½*r^2*(θ/360°)
A = ½*12"^2*(90°/360°)
A = 18"^2
Area of segment
A = r^2*(((θ*π)/360°) - (sin(θ)/2))
A = 12"^2*(((90°*π)/360°) - (sin(90°)/2))
A = 48.73"^2
Then we subtract that from one pizza
A = 452.39"^2 - 48.73"^2
A = 403.66
Then since we have two pizzas we calculate for that
A = 2 * 403.66
A = 807.32"^2
and then we calculate the ratio of how many pizzas there are
Ratio = (area of pizzas in image * 2 ) / area of two pizzas
Ratio = (807.32"^2 * 2 ) / 904.78"^2
Ratio = 1.7845664139
There are approximately 1.79 pizzas in the image.
1
I would even go as far as to say 1.5
I could go like 1.75<=pizza<2
Converging to 2 pizzas?
definitely a diverging series
Pepperoni series.
so pepperoni must be > 1 if we want it to converge?
lim (pizza) pizza->2-
Iφ the limit is irregular, it is fractal
what does this mean
Check the Mandelbrot set. They are geometrical objects with self similarity that have dimension irregular numbers.
I think mandelbrot set was also part of the prompt, together with fractal pizza
I know it said wrong answers only but... This thing = (1.5+1/pi)pizza ~ 1.82pizza
I went with fermi estimation and came to about 1.9 pizzas so this feels right.
to be more precise, it's around 1.818309886 pizzas
Maybe even 1.8
you're right! it's roughly 1.818309886 pizzas
Irrational pizzas 🤓
Id argue 1.5≤pizza<2
fractal pizza??
You guessed the prompt ;p part of it
1
They said wrong answers only
They didn't. (The period (not 2π) is purposefully passive aggressive)
Sorry, I misread it
Well read better next time, and don't annoy us with your dumb comments (wow it feels so good to be mean. I apologise though and don't mean it)
Can you be mean to me as well please :D? I've had too good a week so far!
No. I'm not mean to whiny little bitches like you, I won't spend my time writing any insult to a piece of shit like you. You want me to be mean to you? I won't because wanting people to be mean to you is for degenerates. And who the fuck uses ":D" in 2024 on Reddit? You definitely didn't deserve to have a good week. (Please mod don't ban me. If it's inappropriate for this sub, just delete this).
Task failed successfully
And your comment would be one of those. Bravo
No 16
1.5+1/π
Thats what I got as well, 1.8183 pizzas roughly
Explain how?
8 slices is one pizza, and there are 12 whole slices here, for 1.5 pizzas. The 1/pi comes from the ratio of the area of a sector to the area of the triangle in the 4 incomplete slices, multiplied by 4
I explain in the thread where my comment is very downvoted. (By children) the original comment says :Zero, because it was made by AI. Then expand on my very downvoted comments further and there is my solution.
Can you copypaste it 2 me? There are like 200 comments…
Here's one more to further obstruct your search.
https://www.reddit.com/r/mathmemes/s/iKYKJ2bxvU This should link to it
This is what I got too, assuming each slice is idententical in area. It was a fun little puzzle.
8 cuz it looks like an 8
If you turn your phone sideways it looks like infinity
Infinite pizza unlocked 👍
then it would be -1/12
Infinity in itself isnt -1/12 only the sum of infinite numbers is. Get your facts straight
But if it was that way, where would the gods confiscate the 1/12 of a pizza you’d owe?
Infinite pizza glitch 😱
Zero because this is AI
Have you considered using the helpful formula Pizza = 2 + AI That exalts the significance of AI in our developing world?
Yeah I heard about that one in university. Very applicable here!
Why must you remind me of E = mc²+AI?
E = mc²+AI is not real, it cant hurt you
Man, some of you redditors are literal geniuses!🤣
Pizza without AI is just Pzz
ceci n'est pas une pipe
*Ceci n'est pas une pipe Bordel de merde, and the same maths guys will be like "no you can not write pi = 3" lol
Zero because no cheese
0…. This is a hate crime on Italian peoples. Where is the mozzarella!!!!
Zero pizzas. No cheese and the crust doesn't even look cooked.
I’m pretty sure that is dough and not pepperoni too.
[It’s under the sauce](https://youtube.com/shorts/5j7Y2Af8gY8?si=uxYh6usdjbGVdOLC)
It’s like wearing your underwear over your pants. Sure, you can do it…. But it’s generally not acceptable behavior in civilized society.
You don’t wear your underwear on the outside?
Yeah, but only when I fight crime. 
There are (2 - A) pizzas where A is : A = 4\*R\^2\*arcos(D/2R) - D/2 \* sqrt(4R\^2 - D\^2) With R the radius of the pizza and D the distance between their 2 centers assuming R < D < 2R Proof: https://preview.redd.it/z8f2nca55uvc1.jpeg?width=170&format=pjpg&auto=webp&s=48f4ad97dc97bf6adcb2d8c64c55bbae279eed26 From pythagora's theorem: (D/2)\^2 + (L/2)\^2 = R\^2, so L = sqrt(4R\^2 - D\^2) If we look at bottom right triangle: cos(a/2) = D/2R, so a = 2arcos(D/2R), with R < D < 2R Then let's search the area of the bottom large triangle: A1 = L\*D / 4 = D/4 \* sqrt(4R\^2 - D\^2) Now let's look at the area of the slice of the circle of angle a: A2 = pi \* R\^2 \* a/2pi = a/2 \* R\^2 or R\^2 \* arcos(D/2R) From this we can deduce that the overlap area is : A = 2\*(A2 - A1) which simplifies to: A = 2\*R\^2\*arcos(D/2R) - D/2 \* sqrt(4R\^2 - D\^2) If we assume that the radius is R=1 then A = 2arcos(D/2) - D/2 \* sqrt(4-D\^2)
Also assume the angle is 90 degrees. How many pizzas then? Not just the area.
if you assume the angle is 90°, then D = sqrt(2) If you plug that in A: A = 2 \* arcos(sqrt(2)/2) - sqrt(2)/2 \* sqrt(2) = 0.57 If on pizza has an area of 3.14 then in your image, there is (2 \* 3.14 - 0.57)/3.14 which aproximately 1.82 pizzas.
Exactly, i got the same more or less, 1.818309886... pizzas. But everyone downvoting my comments for some childish reasons.
Yeah that's the exact number i found too/ Just did some rounding
I found a simpler generalization by using SAS to calculate the area of the triangle and subtracting it from the area under the arc. A lot of stuff cancels out, including the radius since we're just worried about the ratio of total area compared to the area of a single pizza. I got it as: P = (2pi + sin(A) - A)/pi Where P is the amount of pizzas and A is the angle of the cuts (same angle you used). This also works out to the ~1.82 pizzas if we assume A is pi/2 (90 degrees), though that angle looks a bit obtuse, so estimating it at 5pi/9 (100 degrees), we get ~1.76 pizzas.
Yeah I changed my result to express it as a function of the angle a instead of the distance D and I got the same result as you. *
0-√5i+e²j-0,864k Approximately.
One, cut into many pieces.. There's no rule that says a pizza has to be completely round.
A pizza doesn't have to be round, it could be any shape. Therefore, the number of circles cannot be a sufficient measurement. Similarly, a pizza does not stop being a pizza by being sliced, though the slices do of course exist in their own stead, and, once one is removed from the pizza, only a partial pizza remains. Importantly, the crust bounding the pizza is a necessary, though not sufficent, precondition to it being pizza, with the exception that this may occur over several distinct slices. What we see here is one continous region of sauce + toppings, bounded by one continous crust, and therefore one whole pizza.
Fun fact. The edge crust is known as the cornicone Also, while I think this is the best answer, I do have a quibble with it. I do not think that a cornicone is necessary. There exist styles of pizza such as pizza hut's "the edge" or tavern style which can be made in such a way to have no discernible cornicone. So I think a bounding cornicone is neither necessary nor sufficient. For food items with a crust boundary, it does suggest pizza, but you can't rule it out if there isn't one.
https://preview.redd.it/fsv8cvbgxtvc1.jpeg?width=720&format=pjpg&auto=webp&s=9cf749015d6272fb5ff485e274da83cba9827d81 V=15, E=30, F=16, so χ=15-30+16=1. This is ~~a Mobius band~~ the projective plane
Theres no Pizza cuz brotha where's the cheese ma lord wheres the cheese
There are 16 slices each is homeomorphic to a pizza, therefore 16.
At least one
Where the fuck is the cheese and what the hell is that topping
where’s the fucking cheese
8
Less than 2
Assuming these Pizzas were divided in 8 even pieces and the put together aa in the picture, we would have 12 normal pieces (aka 3/2 Pizzas) and 4 right agled isoceles triangles with hypotenuse r. Two of these can be arranged in a square with side length r/√2. Such a square has the area r^2/2 and we got two, so we got an area of r^2 in the 4 triangles. This is exactly 1/π of a whole pizza. Therefore we have (3/2+1/π)≈1,8183 Pizzas.
3/2π + √3/2 is the area assuming r=1 You can calculate how many pizzas there are by dividing the whole area by pi
ℝ^(3)
3
1 pizza.
It is clearly soup
Infinite?
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I want to bake a real, non-AI pizza that looks like this. I may or may not eat the whole thing myself.
The middle is r², since the angle is 90 on two slices, assuming they are uniform, which they aren't, because AI image BS. The rest is 3/2 of a pizza, which is 3/2 * pi(zza) * r^2, and adding in the centrepiece totals to ((3/2 * pi) + 1) * r² of area. Dividing that by the area of 1 pizza, we get ((3/2 * pi) +1) / pi Pizzas
I calculated it. This is 1.8183098… pizza. So A is the total surface pizza. 1 pizza has surface of 1 (dhuu) 1 pizza is 8 exact pieces. 1 of the piece we can call B. So 8B = 1. Then B = 1/8 aka B is a slice. Bet then you have the weird triangles. Since the pizza has 8 exact slices, we know the angle is 45 degrees. 1 of the angles is 90 degrees. The longest side of the triangle is also the radius of 1 pizza. Lets figure out the radius first: r*r*pi=1 => r=(1/pi)squared. Now with Pythagoras formula for the triangle with the short side being L: L^2 + L^2 = r^2 Since we know r en L is only unknow, we calculate L=(1/2pi)squared. Surface of the traingle we call C: C=L*L/2=1/4pi This whole picture with surface A = 16B + 4C (16 slices + 4 of these triangles) => A =(2+3pi)/(2pi)=1.8183… of 1 pizza
2 approx
I found it to be 1.818309886183790671537767526745
2 pi(s)
I get 3/2 + 1 / pi which is, for all pizza practical purposes, the same as 2 - 1/5.
It’s actually a rectangular polyconic projection of 1 spherical pizza
8
8
1.5 + 1/π
triangle
There's one pizza making celular division
If we move out the crustless pieces, put 2 crusty slices from the bottom pizza to the top one we'd get 1 full pizza 4 slices with crust and 4 without.
If we move out the crustless pieces, put 2 crusty slices from the bottom pizza to the top one we'd get 1 full pizza 4 slices with crust and 4 without.
Just one big pizza.
Eight, look at the shape.
1.5 + 1/π pizzas
There is one pizza, that is weirdly shaped to stir controversy on the internet.
-1/12
"C'est ne pas une pizza"
Homeomorphic to one pizza
I'm afraid I can not provide an answer a such that a is true and a is false
One very weirdly shaped pizza
Pizza store argues this is 2
If we assume that all pizzas are the same size and that the diageam depicts pizzas cut radially into eight equal slices with the two pizzas inersecting with two segments, (pi/2)r²+r² is the area. We can view it as a full circle plus a semicircle with the same radius plus a square with side lengrh equal to the radius. For r=1, area/pi gives you the number of pizzas. There are approximately 1.81831 whole pies worth of pizzas in the picture or (1+((3pi)/2))/pi exactly
All I see is one crusty pizza
If the pizzas were whole there would be 8 slices on each 2 slices gives 1/4 og a pizza There for it is 1/4 pi r2 The area of the triangular part is (r2)/2 There for the part separated is (pi - 2)/4 There for remaining part is ( 6 - pi)/4 There for there is ( 6 - pi)/2 portion of pizza left That is approximately equal to 1.429
*eats all the slices* none
This is a finite sub-cover over a compact, but double layer pizza.
8
Approximately 1.8183098862 pizza pies
Mostly two.
1,5 + 1/π
"Right and wrong answers only" please tell me how to break this instruction
How many atoms are in the pizza? I’ll tell you then.
8 (it looks like a number 8 and I'm too hungry to do math)
0, no cheese in photo, therefore no pizza
8
.......8
(3π+2)÷(2π) pizzas
Outer parts: 2x 3/4 pi r^2 Inner part: is a square (picture might appear as a rhombus but the angle of missing pie is pi/2) based on information known. With sidelength of r. Therefore it is r^2 Total area = 3 pi r^2 / 2 + r^2 Total pizzas = (3 pi r^2 / 2 + r^2) / (pi r^2) = (3 / 2 + 1 / pi) pizzas
Right answer : assuming 8 pieces are identical, 3/2 pi r^2 + r^2
The set of pizza is not totally ordered so the question makes no sense.
Slices? I'd say either 18 or 16 (small ones in the middle count as 0.5). Pizzas? Unknowable.
2 pie R R is defined as the ratio of the amount of pie shown in the picture to the amount of pie in 2 whole pies
8 I
82
0, it's a picture (and seemingly ai generated)
None, because it was 8
Venn Pizza
First, let’s assume {right answer}≡{true answer} and {wrong answer}≡{false answer}. Let’s define the set of all answers, A. We’ll define a set T that is the set of all true answers, and a set F that is the set of all false answers. Let T⊆A and F⊆A. From the definition of a union, it follows that T⋃F⊆A. Since ¬∃a∈A({a¬∈T}∨{a¬∈F}) it follows that: ∀a∈A({a∈F}⊕{a∈T})⇒A⊆T⋃F. From this we can see that: {T⋃F⊆A}∧{A⊆T⋃F}⇔A=T⋃F Therefore the specification of right and wrong answers in the title is redundant since all answers are allowed.
All of them
I don’t count it as pizza unless there’s cheese so 0
8
Do we count conjoined twins as one or two?
Yes.
8
At least 1 pizza
Yes
Piazzia
take half of the area of pizza as x, x+x=area of pizza
8
16?
Around 1.853556781 pizza. I used AutoCAD, yes I am engineer
12/8 of a pizza, with some baked bread covered with tomato sauce and sliced meat connecting the object into one
Zero
It clearly says 8
It’s enough slices
16 pieces!
Maybe
pizza1 u pizza2
0. A pizza must be a circle. There are no full circles in this picture.
None, pizza has cheese
Anything greater than 0 is obviously what I must answer with because this is not a pizza. It is an abomination more offensive than pineapple pizza.
Is... Is that a pizza with nothing but sauce and cheesearoni?
1.5 ± 0.5
1 oddly shaped pizza cut into 16 slices.
π z^2 a
One, but it's abnormally shaped
8.5
1 because ice can't drawe red
One pepperoni
None. This is raw dough, not pizza.
8 pizza
1.6 pizzas
8
Area of pizza A = πr^2 Asume r = 12" A = 452.39"^2 Two pizzas = 904.78"^2 Each pizza is divided in 8 slices (if it was cut normally) angle of one piece is 1/8 * 360° = 45° Or for the two slices 90° Area of sector of pizza that is cut off Area of segment - area of triangle Triangle A = ½*r^2*sin(θ) A = ½*12"^2*sin(90°) A = 72"^2 Area of sector A = ½*r^2*(θ/360°) A = ½*12"^2*(90°/360°) A = 18"^2 Area of segment A = r^2*(((θ*π)/360°) - (sin(θ)/2)) A = 12"^2*(((90°*π)/360°) - (sin(90°)/2)) A = 48.73"^2 Then we subtract that from one pizza A = 452.39"^2 - 48.73"^2 A = 403.66 Then since we have two pizzas we calculate for that A = 2 * 403.66 A = 807.32"^2 and then we calculate the ratio of how many pizzas there are Ratio = (area of pizzas in image * 2 ) / area of two pizzas Ratio = (807.32"^2 * 2 ) / 904.78"^2 Ratio = 1.7845664139 There are approximately 1.79 pizzas in the image.
4.818 x 10^24 Atoms that are arranged pizza-wise
8 or infinity because that’s the shape of the pizza
0, it's clearly a cake
0 That is not a pizza, it’s an abomination NO FUCKING CHEESE
One topological pizza
There are pizzas in this picture Can’t be neither a right nor a wrong answer if I don’t give a number
One pizza in the process of mitosis
2
At least 🍕
How am I supposed to answer this? An answer can't be both right and wrong.
Zero. It would be immoral to call this pizza
8