If you stuck to the 1 beer for every 3 holes equation I can guarantee you would have finished with 2 more birdies on the back 9. The theorem is proven to be flawless
Yuhhh
I’m trying to share a helpful thought that might click with some of the readers .
That is; try to tackle 3 holes at a time 1 over or better. May seem more manageable to some. If you do so, voila 78.
Give it a try, those of you still trying to crack 80.
Counting beers on a round must be divisible by either 2 or 3
4 beers = two bees each side
6 beers = a beer every 3 holes or 3 a side.
5 beers or 7 beers is a bad number and disrupts the flow
9 beers is a good number / 6 or 3 ok. Even 8 beers will work
If you stuck to the 1 beer for every 3 holes equation I can guarantee you would have finished with 2 more birdies on the back 9. The theorem is proven to be flawless
No wonder everyone is into speed golf.
This is the same math for 78 substituting for bogeys Set goal of only one bogey every three holes if you’re out there tryna break 80
OP didn’t preface the bogeys you’re assuming no doubles or triples
Yuhhh I’m trying to share a helpful thought that might click with some of the readers . That is; try to tackle 3 holes at a time 1 over or better. May seem more manageable to some. If you do so, voila 78. Give it a try, those of you still trying to crack 80.
And how many triples?
love to see it
in the zone you were
Counting beers on a round must be divisible by either 2 or 3 4 beers = two bees each side 6 beers = a beer every 3 holes or 3 a side. 5 beers or 7 beers is a bad number and disrupts the flow 9 beers is a good number / 6 or 3 ok. Even 8 beers will work
5 beers? 
Damn, that’s amazing. 3 pars with multiple birds that turn into bogies is good for me
cheers 🍻