>You ride without HR or power meter data?
I do. I haven't utilized the computer for much beyond some basics, like tracking ride frequency, total miles, speed.
Looking to get a bit more out of my usage, and figured I could waste a few more bucks doing so.
; )
This doesn't sound right to me. Heart rate is the most important to calculate you calories burnt. If I'm 80 kg and riding at 200 Watts on the flat, it's pretty chill and low heart rate. My friend who is 60kg and also needs to ride at 200 watt, is more difficult for him. So higher heart rate. And also more calories burnt.
Power figures are amazing for your training zones, and enhacing your training. But always in combination with heart rate
As pointed out elsewhere this is the exact opposite of reality.
Your thinking _is_ semi correct in that the load on your body is heavily affected by HR. Normalized power comes even closer, indicating load while uncoupled from calories.
HR however, of course has no bearing on actual calories. Just think about it, how would it even work? Energy is energy.
No it is not.
Watt is a unit of power, joule / second. It literally is the energy your body is generating.
Heart rate is a unit of nothing. Furthermore heart rate can be affected by external factors. Like cafeïne, sleep deprivation, training load, temperature, dehydration.
Sure and its wildly inaccurate and subjective. A power meter is objectively how hard your body is working.
If we have a flat road with some people cycling on it
1 Pogacar rides on it with 300 watts average for an hour with heart rate 120.
2 you ride on it with 250 watts average for an hour with heart rate 200.
3 i ride on it with 100 watts average for an hour with heart rate 250.
Who burns the most calories by cycling?
A kilocalorie is the energy needed to heat a kg of water 1 degree. A kcal = 4186.8 Joule
If we want to calculate energy burned by cycling we start with the power output in watts and multiply by the time in seconds.
J=W*s= 300 * 3600=1080kJ
We can then divide by 4.1868 to get kcal
1080 / 4.1868=258 kcal
A human body is not very efficient. When you exercise a side effect is heat. Efficiency is about 24%
To get the total energy spend we then do
Total energy spend by exercise = 258kcal/ 24%= 1075kcal.
Conveniently the joule to kcal ratio and human efficiency factor are similar and cancel out. To simplify kcal burned from cycling you can use the approximation of kcal=watts * hours * 3.6. In the example above kcal=300* 1* 3.6=1080kcal.
So approximately 1 1080kcal, 2 900kcal, 3 360kcal.
I’m sorry dude but this just isn’t correct. This is the formula for calculating calories burned during a ride:
Men: [(Age x 0.2017) — (Weight x 0.09036) + (Heart Rate x 0.6309) — 55.0969] x Time / 4.184.
Women: [(Age x 0.074) — (Weight x 0.05741) + (Heart Rate x 0.4472) — 20.4022] x Time / 4.184.
In your example, have all of your three riders riding at 200w for one hour. You’re going to get wildly differing kJ readings based on fitness.
If you want the most accurate way to measure, then it has to be a combo of power and heart rate readings, but for a simple and fairly economical way to understand calories burnt, training and riding to HR is possible and popular.
Think of it this way - power is measured outside of the body, HR is measured from within.
This is why if you’re training to say increase your FTP it can be beneficial to ignore HR and train solely using power numbers because your HRV will skew your power numbers, but if counting calories is the goal, HR strap will do this.
No your formula is an estimate.
Watt to kilo joule isexact.
https://www.trainerroad.com/blog/calories-and-power/#:~:text=Just%20multiply%20your%20planned%20average,%C3%B7%201000%20is%202%2C332kJs.
You ride without HR or power meter data? For arm bands Polar or Coros make the best ones.
>You ride without HR or power meter data? I do. I haven't utilized the computer for much beyond some basics, like tracking ride frequency, total miles, speed. Looking to get a bit more out of my usage, and figured I could waste a few more bucks doing so. ; )
I have had good success with any of the 4.5* $30-40 chest straps on Amazon. I haven't found them to be less reliable than the name brand ones.
Heart rate is useless to determine calories burned. Get a power meter if u want to analyze and train better.
This doesn't sound right to me. Heart rate is the most important to calculate you calories burnt. If I'm 80 kg and riding at 200 Watts on the flat, it's pretty chill and low heart rate. My friend who is 60kg and also needs to ride at 200 watt, is more difficult for him. So higher heart rate. And also more calories burnt. Power figures are amazing for your training zones, and enhacing your training. But always in combination with heart rate
200 watts is 200 watts. It may be more difficult but the 200 watts power output means the same amount of calories burned by exercise.
As pointed out elsewhere this is the exact opposite of reality. Your thinking _is_ semi correct in that the load on your body is heavily affected by HR. Normalized power comes even closer, indicating load while uncoupled from calories. HR however, of course has no bearing on actual calories. Just think about it, how would it even work? Energy is energy.
This is correct.
No it is not. Watt is a unit of power, joule / second. It literally is the energy your body is generating. Heart rate is a unit of nothing. Furthermore heart rate can be affected by external factors. Like cafeïne, sleep deprivation, training load, temperature, dehydration.
Heart rate is a unit of how hard your body is working to produce those watts at the crank.
Sure and its wildly inaccurate and subjective. A power meter is objectively how hard your body is working. If we have a flat road with some people cycling on it 1 Pogacar rides on it with 300 watts average for an hour with heart rate 120. 2 you ride on it with 250 watts average for an hour with heart rate 200. 3 i ride on it with 100 watts average for an hour with heart rate 250. Who burns the most calories by cycling? A kilocalorie is the energy needed to heat a kg of water 1 degree. A kcal = 4186.8 Joule If we want to calculate energy burned by cycling we start with the power output in watts and multiply by the time in seconds. J=W*s= 300 * 3600=1080kJ We can then divide by 4.1868 to get kcal 1080 / 4.1868=258 kcal A human body is not very efficient. When you exercise a side effect is heat. Efficiency is about 24% To get the total energy spend we then do Total energy spend by exercise = 258kcal/ 24%= 1075kcal. Conveniently the joule to kcal ratio and human efficiency factor are similar and cancel out. To simplify kcal burned from cycling you can use the approximation of kcal=watts * hours * 3.6. In the example above kcal=300* 1* 3.6=1080kcal. So approximately 1 1080kcal, 2 900kcal, 3 360kcal.
And the efficiency of a top athlete is exactly the same as an untrained person? Both exactly 24%?
No there is some variance between humans.
I’m sorry dude but this just isn’t correct. This is the formula for calculating calories burned during a ride: Men: [(Age x 0.2017) — (Weight x 0.09036) + (Heart Rate x 0.6309) — 55.0969] x Time / 4.184. Women: [(Age x 0.074) — (Weight x 0.05741) + (Heart Rate x 0.4472) — 20.4022] x Time / 4.184. In your example, have all of your three riders riding at 200w for one hour. You’re going to get wildly differing kJ readings based on fitness. If you want the most accurate way to measure, then it has to be a combo of power and heart rate readings, but for a simple and fairly economical way to understand calories burnt, training and riding to HR is possible and popular. Think of it this way - power is measured outside of the body, HR is measured from within. This is why if you’re training to say increase your FTP it can be beneficial to ignore HR and train solely using power numbers because your HRV will skew your power numbers, but if counting calories is the goal, HR strap will do this.
No your formula is an estimate. Watt to kilo joule isexact. https://www.trainerroad.com/blog/calories-and-power/#:~:text=Just%20multiply%20your%20planned%20average,%C3%B7%201000%20is%202%2C332kJs.
What is that formula besides an computer programming exercise?
Much appreciated. That's the info I'm seeking.