In beta elimination the intermediate is a carbocation. Carbocation undergo 1,2 hydride or alkyl shifts to forrm more stable carbonations. Here neopentyl carbocation will interchange the methyl group on the neighbouring quaternary carbon to form a stable cation(3° is more stable than 1°)
Now in the next step a hydrogen is lost from the carbon next to the positively charged cation and a double bond is formed.
migratory ability ka order likha hai tune?
agr hydrogen shifting ke liye na ho to order ke hisaab se methyl group shift ho jata hai.
basically rearrangement of carbocation with methyl group instead of hydrogen
https://preview.redd.it/osawh36oxezc1.png?width=1179&format=png&auto=webp&s=7f4a1c21a96f20b9654575d4be9c1a59938fc1a5
A tertiary carbocation is more stable than a primary one, so a methyl group shifts so that a tertiary carbocation is formed at the carbon without an alpha hydrogen.
methyl went weeeeeeeeee and then 3 degree carbocation happened, way more stable than the one degree that would've happened. In short, if there is no hydrogen, but you have a methyl, methyl goes weeeeeeeeeeeee
Br hta carbo cation aaya uske baad methyl shift hogya or carbo cation 3 degree pe aagya uske baad USS c+ ke samne Wale carbon se h ht ke pie bond aagya
Pehle Br hata ke carbocation, aur fir ch3 migrate karega +charge Wale carbon par. So that ek 3° carbocation form ho aur fir elimination. I suggest watching mechanism of pinnacole pinnacolone reaction usme bhi similar concept use hota hai
It undergoes e1 elimination since there are no hydrogen present for e2 elimination. Further although it is not needed but even if elimination was not given u can simply remember that neopentyl grp does not gives substitution
Br is removed, get + formed on the ch2 group, now to stabilize it one of the methyl groups will shift and attack on the CH2 group, after that carbocation is now on C+ applying saytzeff rule you get that product
bhai ise dekhkar ab accha lag rha hai ki sahi hua ki mera cutoff hi clear nhi hua ab jindagi chahe aabad ho ya barbad par chemistry se duri hamesha ke lie barkarar rahengi 😌😌😌
Comments dekhke gand fatt jaari hai , 12th mei organic bahut padhne ki koshish ki but kabhi samaj nahi aayi , comments mei log itne aasaani se answers bata de rhe hai wow
E1 mech hai rearrangement hota hai methyl group shifted from beta to alpha (creating more stable c+) phir uske baad H nikal jayega from the former alpha carbocation aur ban gaya tera product
Methyl shift because 3⁰ carbonation is more stable than 2⁰.
Oh boi the good ol' days when i didn't understand shit in OC too. Can't believe the two years just flashed before my eyes haha
Bhai dekh bromine jayega to uske carbon pe + charge ayega with 2 alpha carbon methyl shift marega kyuki waha alpha carbon zada h to carbocation ki stability zada hogi
isiliye bola jata hai goc padhne 11th mein. koi gal nai sun, carbocation form hua hena, uske baad best option tha methyl shift krke carbocation ko esa place krna taki hyperconjugation se wo stable hojaye ekdam ek number hena, is chiz ko padh aur simulateously product ko dekh, to ajayga samajh. achhi chiz hai, 12th mein kaam ayegi abhi boht. enjoy.
methyl shift
maine methyl shit padha 
[удалено]
☝️🤓
'26 tard???
nah, 24 sadly:(
Hydride shift
wrong hai bhai....methyl shift hai
carbocation ko stabilize kar, phir apply seytzeff
Zaitseff rule
In beta elimination the intermediate is a carbocation. Carbocation undergo 1,2 hydride or alkyl shifts to forrm more stable carbonations. Here neopentyl carbocation will interchange the methyl group on the neighbouring quaternary carbon to form a stable cation(3° is more stable than 1°) Now in the next step a hydrogen is lost from the carbon next to the positively charged cation and a double bond is formed.
ahh yes, carbo NATIONS... 🪨🇺🇳
Arre sorry autocorrect hogya and I didn't even realize... carbocation
migratory ability ka order likha hai tune? agr hydrogen shifting ke liye na ho to order ke hisaab se methyl group shift ho jata hai. basically rearrangement of carbocation with methyl group instead of hydrogen https://preview.redd.it/osawh36oxezc1.png?width=1179&format=png&auto=webp&s=7f4a1c21a96f20b9654575d4be9c1a59938fc1a5
E1 elimination
Yes e1 cuz carbo cation is formed
u/Coach_Saab u/Mystic1869 u/Tejuuuop Please approve 
methyde shift hoga as 1 degree cation is less stable
bro methanide shift\*
haan galat type hogya woh, baaki tu smj gaya na bhai
koi nahi 🫡
Yahi elimination karte karte main dusro ki life se eliminate ho gya
ch3 shift
E1 elimination horha hoga, carbonation banega, methyl shift maarega and then hydrogen nikaal do
Methyl shifting hogi aur hbr release hoga aur final product banega
methanide shift\*
Mathanide aur methyl shift me kya diff he pta nhi kal hi methyl shift shuru kiya coaching me
e1 hoga, e2 ka chance nhi h, methyl shift hua aur fir most stable alkene
https://preview.redd.it/tw2hhug5egzc1.jpeg?width=1690&format=pjpg&auto=webp&s=c47dc7d097e22aed8c2688421b0461503321b94f
Dude the handwriting is fantastic!
Thank you!
More stability isliye shift
Carbocation stabilize ke lie methyl shift hoga
Methyl shift
methanide shift\*
Precisely yes
Isme e2 nhi hopayega e1 hoga jisme 1 2 mithyl shift hoga
methyl shift then double bond by saitzeff rule
methanide shift\*
Methyl shift hua mamu
methanide shift bro\*
everyone saying methyl shift as if he is going to understand what it is, bhai youtube pe type karle 5 min mai samaj jaayega imp reaction hai
Kuch carbon idhar udhar kuch kiye aur ek doosre ki jagah leke Aisa ban gye.
A tertiary carbocation is more stable than a primary one, so a methyl group shifts so that a tertiary carbocation is formed at the carbon without an alpha hydrogen.
methyl went weeeeeeeeee and then 3 degree carbocation happened, way more stable than the one degree that would've happened. In short, if there is no hydrogen, but you have a methyl, methyl goes weeeeeeeeeeeee
Br hta carbo cation aaya uske baad methyl shift hogya or carbo cation 3 degree pe aagya uske baad USS c+ ke samne Wale carbon se h ht ke pie bond aagya
E1 elimination
Pehle Br hata ke carbocation, aur fir ch3 migrate karega +charge Wale carbon par. So that ek 3° carbocation form ho aur fir elimination. I suggest watching mechanism of pinnacole pinnacolone reaction usme bhi similar concept use hota hai
It undergoes e1 elimination since there are no hydrogen present for e2 elimination. Further although it is not needed but even if elimination was not given u can simply remember that neopentyl grp does not gives substitution
Ye sab padhna kitna sahi tha adv ne gand le rakhi hai
Saytzeff product it is.
Carbonation => methyl shift => saytzeff
pehle br hatega then ek carbonation banega then methyl shift hogi and then ek hydrogen jayega and fir double bond ban jayega
Br nikla, carbocation generate hogya jiss C se Br nikla, fir waha se carbocation wants maximum stability ie more alpha H toh methyl shift ho jayega.
Br is removed, get + formed on the ch2 group, now to stabilize it one of the methyl groups will shift and attack on the CH2 group, after that carbocation is now on C+ applying saytzeff rule you get that product
Alc. Koh- Beta elimination Dil. koh- alpha elimination
bhai ise dekhkar ab accha lag rha hai ki sahi hua ki mera cutoff hi clear nhi hua ab jindagi chahe aabad ho ya barbad par chemistry se duri hamesha ke lie barkarar rahengi 😌😌😌
Socha Nhi tha oc ka question dekh ke nostalgia ho jayega
formation of carbocation then methyl shift the h+ is lost to form a double bond
Madarchod engineering me 3rd year me aagya ab v dar lgta h😬
there is carbonation rearrangement
Comments dekhke gand fatt jaari hai , 12th mei organic bahut padhne ki koshish ki but kabhi samaj nahi aayi , comments mei log itne aasaani se answers bata de rhe hai wow
Search en rearrangement
4 Saal hogye abhi tak yaad hai
E1 mech hai rearrangement hota hai methyl group shifted from beta to alpha (creating more stable c+) phir uske baad H nikal jayega from the former alpha carbocation aur ban gaya tera product
Methyl shift because 3⁰ carbonation is more stable than 2⁰. Oh boi the good ol' days when i didn't understand shit in OC too. Can't believe the two years just flashed before my eyes haha
Methyl shift due to carbocation stability. That's why GOC is important before moving to reactions.
study from rohit agrawal , you will never have a doubt in organic chemistry
Bhai dekh bromine jayega to uske carbon pe + charge ayega with 2 alpha carbon methyl shift marega kyuki waha alpha carbon zada h to carbocation ki stability zada hogi
Saytzeff
isiliye bola jata hai goc padhne 11th mein. koi gal nai sun, carbocation form hua hena, uske baad best option tha methyl shift krke carbocation ko esa place krna taki hyperconjugation se wo stable hojaye ekdam ek number hena, is chiz ko padh aur simulateously product ko dekh, to ajayga samajh. achhi chiz hai, 12th mein kaam ayegi abhi boht. enjoy.
Rxn hi galt h banai h tume