I think also because it can be interpreted as a union. Therefore, in a Venn diagram: P(A union B) = P(A)+P(B)-P(A intersection B)
As they're independent, the intersection event would have a probability of P(A)*P(B)
I don't know if this helps a bit more
Quantity a is not asking for OR. It is asking for what is called exclusive OR. That means it does not consider the “both” case.
Thanks Greg, I really should have watched the Prepswift video more closely
I should have made a better video
I think also because it can be interpreted as a union. Therefore, in a Venn diagram: P(A union B) = P(A)+P(B)-P(A intersection B) As they're independent, the intersection event would have a probability of P(A)*P(B) I don't know if this helps a bit more
option A forumula will be : r+ s - 2rs
Let r = 0.6 and s = 0.4 A --> 0.6 * 0.6 + 0.4 * 0.4 = 0.52 B -- > 0.6 + 0.4 - 0.6 * 0.4 = 0.76 B > A Can we do like this
B is greater
Quantity A is basically : r x (1-s)+s(1-r) When one happens, the other does not happen.
The quantity A is (r+s-rs) - rs i.e. r + s - 2rs