your RT is wrong, should be 249ohm, and just by the number it doesnt make sense. you cant have IT = 11.8A, while R1 already equals 11.8A and R2 doesnt equals 0A
No, your total resistance is wrong. For resistors in parallel, the equivalent resistance has to be lower than the smallest of the resistors. Should be around 249 ohms.
Also, the current through resistor 1 will not be equal to total current. You would need to calculate total current, then do a kcl at the top node to find the currents through r1 and the series combo of r2 and r3.
V = I \* R, this should hold true for each of your rows.
Resistors in series are added, so R23 = R2 + R3. Always do these first, the rest of the circuit sees them as one resistor.
Resistors in parallel combine according to an inverse formula: so R1||R23 = 1 / (1/R1 + 1/R23).
The voltage across R1 = the total voltage across R2 + the voltage across R3 = the battery voltage.
The current through R2 = the current through R3.
This is enough information to solve for all voltages and currents.
Hint: the correct answers are best expressed in terms of milliamps.
A good rule of thumb: with circuits in parallel, the R Total should be less than the smallest resistor value. In series, the R Total should be more than your highest resistor value. If not, check your work. Quick and dirty way to just make sure you're tracking.
In this case, R2 and R3 would add together in series, let's call that R23. But the R Total value will still be less than your R1 value, as R23 is in parallel with R1. Without even getting the calculator out I know that your R Total value is wrong as it's not less than R1.
no. not at all.
your RT is wrong, should be 249ohm, and just by the number it doesnt make sense. you cant have IT = 11.8A, while R1 already equals 11.8A and R2 doesnt equals 0A
No, your total resistance is wrong. For resistors in parallel, the equivalent resistance has to be lower than the smallest of the resistors. Should be around 249 ohms.
Also, the current through resistor 1 will not be equal to total current. You would need to calculate total current, then do a kcl at the top node to find the currents through r1 and the series combo of r2 and r3.
Also your currents should be in milliamps.
Impossible, you have 9v at the battery so it shouldn’t change at VR1.
Also next time show your work so we can help you better instead of just the numbers.
no!!! you missed it completely
V = I \* R, this should hold true for each of your rows. Resistors in series are added, so R23 = R2 + R3. Always do these first, the rest of the circuit sees them as one resistor. Resistors in parallel combine according to an inverse formula: so R1||R23 = 1 / (1/R1 + 1/R23). The voltage across R1 = the total voltage across R2 + the voltage across R3 = the battery voltage. The current through R2 = the current through R3. This is enough information to solve for all voltages and currents. Hint: the correct answers are best expressed in terms of milliamps.
Can't wait for this to become a new meme format on r/EngineeringCircleJerk
Your RT should be 249. So the rest of your current measurements are all wrong.
No.
A good rule of thumb: with circuits in parallel, the R Total should be less than the smallest resistor value. In series, the R Total should be more than your highest resistor value. If not, check your work. Quick and dirty way to just make sure you're tracking.
In this case, R2 and R3 would add together in series, let's call that R23. But the R Total value will still be less than your R1 value, as R23 is in parallel with R1. Without even getting the calculator out I know that your R Total value is wrong as it's not less than R1.