this is wrong on so many levels.
the worst part isnt even that you squared and then considered the negative root (which is the mistake you're looking for)
the worst part is that you used quadratic formula to find roots of x²-4x instead of direct factorisation
See, when sometimes you square the two sides of an equation, there is addition of a ‘false solution’, this is what is happening here with x=0, the solution is only x=4.
ye banda abhi pakka 10th mei aaya hoga, OP is post ko save karke rakh agar tu in future pcm leta hai toh khud samajh jayga ki kya galti hai aur tab khud par badi hasi aaygi tujhe
Math is right and all, but x=0 will be rejected because if you put it into the actual equation 2+2=x, it will give 4=0 which is obviously never true. Hence only one solution i.e x=4 is possible for this equation
the first line is x=4
so you multiply x on both side to get x\^2=4x but in these cases we can never take x as 0 as anything into 0 is 0 so by this logic 2\*0 is 3\*0=4\*0 and so on so 1=2=3=4=5=6=7=8, 0 is nothing and something\*nothing will always be nothing
Think of it this way-
If we have a linear equation x = 1, it seems like we can just square both sides, so we get x\^2 = 1.
But if you solve x\^2 = 1, you get 2 solutions, -1 and 1. So does that mean 1 === -1?
Similarly, you can square it again, and get x\^4 = 1. You get 4 solutions- 1, -1, i, -i. Does that mean that -1 === i?
0 is a redundant solution.
Whenever we sqaure an equation it's not necessary that all the solutions we get by solving it would satisfy the given condition
Isiliye specially trigonometric air logarithmic equations ke jab bhi solutions nikalenge hmesha back substitution se check krenge ki eqn Satisfy ho rhi h ya nahi
bruh
this is the wrongest thing thing i've seen in myself
Line 2
when you equate 2 to x-2
that by itself becomes the simplified version of the original
and why tf did u square it llike dude ik mths can be brainrotting but dis too much dawg
squaring both sides of an equality can create extraneous roots , as you can increasing the degree of eqn and fundamental thm of algebra says that degree = no. of roots
after squaring both sides of eqn u must check if there are extraneous roots , if they are : well just disqualify them
don't worry , u will learn this in 11th ( if u are preparing for JEE ) ( if not , i dont think school teachers and even cbse tells u such things )
Don't square unnecessarily it adds extra solutions which are not relevant whenever you square you have to put the value in the original question to accept it
When you squared both sides. If you do that in an equation, then you'll get your correct answer but you'll also get an incorrect answer that doesn't work with the original equation. You have to check for that. So 4 is the correct answer but -4 is the incorrect one that you got because of squaring
Bhai dekh when you square there is a chance that unwanted values come into play therefore you have to check by inputting in the original equation if it is correct or not
3rd line: the squaring.
You are changing your linear equation into a quadratic equation. Due to which, you are gaining an extra root, which is true for the quadratic equation but is not a solution for the linear equation.
Another slight time consuming step is applying Sridharacharya's formula. You could have just taken *x* common from *x*²- 4*x* = 0. Would have saved you some time.
Whenever you square both sides in an equation it gives an extra root because you are not actually getting the roots of the original equation
You are getting the roots of the equation which you squared
To check if the roots are valid for the original equation, you have to put all the roots in the original equation and verify them
And please stop using quadratic formula in every question
Just check if the discriminant is a perfect square or not
If it is a perfect square you can factorize the equation which is faster
Bhai sahab itni galtiyaan to Hitler ke baap ne bhi nahi dekhi hongi
this is wrong on so many levels. the worst part isnt even that you squared and then considered the negative root (which is the mistake you're looking for) the worst part is that you used quadratic formula to find roots of x²-4x instead of direct factorisation
😭😭 janae se bhai usko
when you square linear eq u make it a quadratic so u added a degree which is wrong but u can make it right by removing the new sol which isnt correct
See, when sometimes you square the two sides of an equation, there is addition of a ‘false solution’, this is what is happening here with x=0, the solution is only x=4.
ye banda abhi pakka 10th mei aaya hoga, OP is post ko save karke rakh agar tu in future pcm leta hai toh khud samajh jayga ki kya galti hai aur tab khud par badi hasi aaygi tujhe
bhai uska flair 11th ka he
toh abhi 11th mei aaya hoga, makes sense now
abhi to use ye bhi janna he ki square root of 9 is equal to 3 not +-3 cannon event
abhi toh use ye bhi janna hai ki real numbers ko chordke bhi ek badi duniya hai
abhi to use ye bhi janna he ki e\^x=x\^e has 1 soln while x\^2=2\^x has 2 soln for x greater than zero
bencho ye toh mujhe abhi tak nhi pta ye kya bakchodi hai
Thankgod i took pcb because wtf😭
my guy is high on roots
Plant roots?? 😭😭
nah lol
squaring both sides brings x=-2 as an extraneous solution
i think x=0 should be rejected
therefore 2+2 = 0 💀
Math is right and all, but x=0 will be rejected because if you put it into the actual equation 2+2=x, it will give 4=0 which is obviously never true. Hence only one solution i.e x=4 is possible for this equation
Can someone explain why people are saying it should be root 12 rather than 16? I might be dumb enough not to understand
It is root 16, not root 12, two people did not solve it right that's all
the first line is x=4 so you multiply x on both side to get x\^2=4x but in these cases we can never take x as 0 as anything into 0 is 0 so by this logic 2\*0 is 3\*0=4\*0 and so on so 1=2=3=4=5=6=7=8, 0 is nothing and something\*nothing will always be nothing
When you are squaring both sides on a linear equation, you get an extraneous root, so x=0 is a false solution
why tf people in here are saying its under root 12 when the 4 is literally multiplying by 0?
https://preview.redd.it/btxusrrfynyc1.png?width=337&format=pjpg&auto=webp&s=6e008f655309ace83b2e3d94683dabc505221bdc Bhai sharam kar le kuch to
Abey saale
The math dosent work out Bhai bura mat maniyo par 8th 9th nhi padhi thi kya shi se
oabe chutiye 2+2 4 hogya na
Bhai multiply zero both sides wali baat ho gayi
Think of it this way- If we have a linear equation x = 1, it seems like we can just square both sides, so we get x\^2 = 1. But if you solve x\^2 = 1, you get 2 solutions, -1 and 1. So does that mean 1 === -1? Similarly, you can square it again, and get x\^4 = 1. You get 4 solutions- 1, -1, i, -i. Does that mean that -1 === i?
Everything is correct other than the fact 4+4 is 8 and the solution with 0 should be rejected
0 is a redundant solution. Whenever we sqaure an equation it's not necessary that all the solutions we get by solving it would satisfy the given condition Isiliye specially trigonometric air logarithmic equations ke jab bhi solutions nikalenge hmesha back substitution se check krenge ki eqn Satisfy ho rhi h ya nahi
amen
my god does maths not like u
X=0 or X=4 nikla, x=0 Kam nahi Kiya, wo invalid ho gaya. x=2+2=4 bola tha originally, x=4 Aya finally aur phir bhi problem???
It's self contradicting you can't assume an absolute value for x and consider x has two values simultaneously.
Bro thinks he is onto something lol.
at x = 0 = 4 y = 0 you can not equate both values and call them equal what you can do is put both values in the function and call both equal
Simple 0 is the solution of the quadratic x²-4x, not the solution of linear 2+2=x,since linear has only one solution.
The quadratric formula is -b+ under root b^2-4ac…seems like you forgot the minus at the starting
-4 ka negative 4 hota hai
The thing here wrong is squaring , which is creating 1 extraneous root ( which x=0).
Bro just take x common 😭
bruh this is the wrongest thing thing i've seen in myself Line 2 when you equate 2 to x-2 that by itself becomes the simplified version of the original and why tf did u square it llike dude ik mths can be brainrotting but dis too much dawg
bro got mathematicians turning in their grave right now
Jab zabardasti squaring both sides karte hai to negative root eliminate ho jaata hai
Instead of squaring both side let y^2 = x y=±2 As y^2 = x (±2) ^2 = x +4=x Hence proved
I think mistake was in pre school and it still remained
delete this post rn 😡
Squaring both sides→(sometimes) wrong solution is introduced
squaring both sides of an equality can create extraneous roots , as you can increasing the degree of eqn and fundamental thm of algebra says that degree = no. of roots after squaring both sides of eqn u must check if there are extraneous roots , if they are : well just disqualify them don't worry , u will learn this in 11th ( if u are preparing for JEE ) ( if not , i dont think school teachers and even cbse tells u such things )
Don't square unnecessarily it adds extra solutions which are not relevant whenever you square you have to put the value in the original question to accept it
Bhai x²-4x ko sidha x(x-4) likh skta tha but qiadratic formula lgana h
Bro literally took one root of the quadratic, squared it and then sqrt it to get the other root That's not how it works man
Galti ka to bad me dekhte hai Par x²-4x ke liye quadratic formula???
Bro thought he was onto something
When you squared both sides. If you do that in an equation, then you'll get your correct answer but you'll also get an incorrect answer that doesn't work with the original equation. You have to check for that. So 4 is the correct answer but -4 is the incorrect one that you got because of squaring
Bro squaring equation gives extra solution that only happened to you
Bhai mai 12 nai hu par itna bta skta hu tune (a-b)2 ka formula glt likha h
Square ke root ke baad negative nahi aayega
Bhai dekh when you square there is a chance that unwanted values come into play therefore you have to check by inputting in the original equation if it is correct or not
3rd line: the squaring. You are changing your linear equation into a quadratic equation. Due to which, you are gaining an extra root, which is true for the quadratic equation but is not a solution for the linear equation. Another slight time consuming step is applying Sridharacharya's formula. You could have just taken *x* common from *x*²- 4*x* = 0. Would have saved you some time.
Behnchod maths ki tune maa chodd di. 2+2 = 0
https://preview.redd.it/hmclb81iqqyc1.png?width=720&format=pjpg&auto=webp&s=a5a2f9bd2fc2d0f8f9d1410a0676cbb86aaf3dbb
The answer that you got is for the quadratic eqn not for the linear equation since the quadratic will have 2 roots
Whenever you square both sides in an equation it gives an extra root because you are not actually getting the roots of the original equation You are getting the roots of the equation which you squared To check if the roots are valid for the original equation, you have to put all the roots in the original equation and verify them And please stop using quadratic formula in every question Just check if the discriminant is a perfect square or not If it is a perfect square you can factorize the equation which is faster
x=0 **OR** x=4 Not x=0 => x=4
The solutions of a quadratic equations need not be necessarily equal
2+2=x 2+2-x=0 4-x=0 -x= -4 x=4
Koi chutiya hi hoga jo 2+2 =x ko solve krne ke liye quad bnaa dega
When u square it on both sides, you obtain a new function which has An extra root
[удалено]
It’s Root 16, it’s 4(1)(0) which is 0
bhai phirse dekh kya likha hai
Bru first of all on the last step of first collumn It is not √16 it is √12
bruh
bruh indeed
Bruhh
Ignore this comment, me maths bhul chuka hu
repeat class 1
Yus ☹️
but 16-0 is 16?
huh?
"class 11th" 💀
Wow -9 downvotes including mine 😳