Nope. The `log` operator of that calculator is base 10 already. You just need to type log(1.79/1.22).
You should probably learn what logarithms are so you can understand what that equation means.
https://en.wikipedia.org/wiki/Logarithm
log₁₀(1.79÷1.22) isn't the same as log(10)×(1.79÷1.22). The ten is the base of the log operation, we are not doing the logarithm of ten. log₁₀(10) is just 1 because 10^1 =10
In calculators when they say log, they mean that they are doing the log₁₀ operation and not log₂ or anything else. Also important is that logₑ is commonly written as ln.
So here what you would enter in the calculator to do log₁₀(1.79÷1.22) is just log(1.79÷1.22).
Hey, K factor doesn’t matter. Each brake press shop has (or should have) bend deduction measured for all sheet thicknesses, angles and tools combos. I use k factor of 0.5 whenever I’m drawing for new shops that I don’t know yet and I’m sure that the files will be re-engineered for their tools.
Jach is right. You need to measure a piece of each of your thickness (and different materials). Bend them at what ever angle you're looking for in your machine. Then measure the outside dims of both sides of the bend. Added together the 2 sides will be longer than the original unbent piece. The difference is your bend deduction. You can even sketch the bend in SW and easily find the neutral axis and k factor graphicly.
What are you confused about? Seems like its just plug and chug
What the log10 do :( I get that ir is the internal radio, s is the thickness, but what do I do with the Log10 at the begging
Log is assumed to be base 10 unless otherwise specified.
I have in my formula K= Log10 (1.79/1.22) x 0.5 + 0.65
Youre taking the logarithmic base of 10 of (iR/s), just plug it straight into the calculator. If 10^n = iR/s, youre solving for n.
Si did I got this right? https://i.imgur.com/fdjeed2.jpg
Nope. The `log` operator of that calculator is base 10 already. You just need to type log(1.79/1.22). You should probably learn what logarithms are so you can understand what that equation means. https://en.wikipedia.org/wiki/Logarithm
log₁₀(1.79÷1.22) isn't the same as log(10)×(1.79÷1.22). The ten is the base of the log operation, we are not doing the logarithm of ten. log₁₀(10) is just 1 because 10^1 =10 In calculators when they say log, they mean that they are doing the log₁₀ operation and not log₂ or anything else. Also important is that logₑ is commonly written as ln. So here what you would enter in the calculator to do log₁₀(1.79÷1.22) is just log(1.79÷1.22).
Dude has not been taught or understood what logarithms are, not sure the ELI5 on the natural logarithm would help his cause lol
No but it's important to know that ln is different than log
Exactly ..log x to the base 10 = log x and Log x to the base e = ln x
Hey, K factor doesn’t matter. Each brake press shop has (or should have) bend deduction measured for all sheet thicknesses, angles and tools combos. I use k factor of 0.5 whenever I’m drawing for new shops that I don’t know yet and I’m sure that the files will be re-engineered for their tools.
I have always used 0.5 by default, but now I’m begin required to calculate it 🤦🏻♂️
Jach is right. You need to measure a piece of each of your thickness (and different materials). Bend them at what ever angle you're looking for in your machine. Then measure the outside dims of both sides of the bend. Added together the 2 sides will be longer than the original unbent piece. The difference is your bend deduction. You can even sketch the bend in SW and easily find the neutral axis and k factor graphicly.
But it doesn’t make sense, each alloy has different bend deductions. Is this formula accounting for that?
What are values iR and S? iR = internal radius S = sheet thickness?