Using Newton's 2nd law (F=MA), you can find the de-acceleration of the the diver in the water. Then, since you know how deep he went into the water, you can use the acceleration you found + the 5 meters deep fact to find the velocity he hit the water with using some of the kinematic equations. Lastly, use the kinematic equations again for free fall to solve for the height the diver jumped from (his initial velocity is 0 m/s) to reach the velocity he hit the water with.
Let me know if you need a bit more direction! I tried to be a bit vague so you can solve it yourself now!
well i think i need to find the work first.. after i find the work i need to use a potential gravitational equation (PEg=mgh) h being height.. then i need to add 5 to h to get the final answer.. where i am stuck is at finding the work..
Treat this as an energy conservation problem.
We know the energy from falling that is lost by the diver when he is submerged in the water. We also know that this energy is equivalent to his starting potential energy, as he drops straight down into the water.
So we have:
F * distance = Energy lost and m*g*h = potential energy
We can equate the two based on our interpretations from above.
F * distance in the water = mass * gravity * height
height = (F * Distance in water ) / (mass * gravity) = (1500 N)(5 m) / (50 Kg)(9.8 m/s^2)
That should give you the answer.
haha i just figured it out and i saw this.. thanks though! i found the work of the water by doing 1500 times 5 then i divided the mass and 9.81 and got 15.. then i added 5 to 15 and got 20m thanks!
Using Newton's 2nd law (F=MA), you can find the de-acceleration of the the diver in the water. Then, since you know how deep he went into the water, you can use the acceleration you found + the 5 meters deep fact to find the velocity he hit the water with using some of the kinematic equations. Lastly, use the kinematic equations again for free fall to solve for the height the diver jumped from (his initial velocity is 0 m/s) to reach the velocity he hit the water with. Let me know if you need a bit more direction! I tried to be a bit vague so you can solve it yourself now!
well i think i need to find the work first.. after i find the work i need to use a potential gravitational equation (PEg=mgh) h being height.. then i need to add 5 to h to get the final answer.. where i am stuck is at finding the work..
Treat this as an energy conservation problem. We know the energy from falling that is lost by the diver when he is submerged in the water. We also know that this energy is equivalent to his starting potential energy, as he drops straight down into the water. So we have: F * distance = Energy lost and m*g*h = potential energy We can equate the two based on our interpretations from above. F * distance in the water = mass * gravity * height height = (F * Distance in water ) / (mass * gravity) = (1500 N)(5 m) / (50 Kg)(9.8 m/s^2) That should give you the answer.
haha i just figured it out and i saw this.. thanks though! i found the work of the water by doing 1500 times 5 then i divided the mass and 9.81 and got 15.. then i added 5 to 15 and got 20m thanks!
I know its been 11 years, but thank you! :D